[SQL : 프로그래머스] DATETIME에서 DATE로 형 변환

문제

SELECT
    ANIMAL_ID,
    NAME,
    date_format(DATETIME, '%Y-%m-%d') AS '날짜'
FROM
    ANIMAL_INS
ORDER BY
    ANIMAL_ID

쉬운 문제의 경우 되도록 포스팅을 자제하려고 하는데
date_format 함수의 포맷에 관해 깨달은 점이 있어서 ㅡㅡ;;

%a : Abbreviated weekday name (Sun..Sat)
%b : Abbreviated month name (Jan..Dec)
%c : Month, numeric (0..12)
%D : Day of the month with English suffix (0th, 1st, 2nd, 3rd, …)
%d : Day of the month, numeric (00..31)
%e : Day of the month, numeric (0..31)
%f : Microseconds (000000..999999)
%H : Hour (00..23)
%h : Hour (01..12)
%I : Hour (01..12)
%i : Minutes, numeric (00..59)
%j : Day of year (001..366)
%k : Hour (0..23)
%l : Hour (1..12)
%M : Month name (January..December)
%m : Month, numeric (00..12)
%p : AM or PM
%r : Time, 12-hour (hh:mm:ss followed by AM or PM)
%S : Seconds (00..59)
%s : Seconds (00..59)
%T : Time, 24-hour (hh:mm:ss)
%U : Week (00..53), where Sunday is the first day of the week; WEEK() mode 0
%u : Week (00..53), where Monday is the first day of the week; WEEK() mode 1
%V : Week (01..53), where Sunday is the first day of the week; WEEK() mode 2; used with %X
%v : Week (01..53), where Monday is the first day of the week; WEEK() mode 3; used with %x
%W : Weekday name (Sunday..Saturday)
%w : Day of the week (0=Sunday..6=Saturday)
%X : Year for the week where Sunday is the first day of the week, numeric, four digits; used with %V
%x : ear for the week, where Monday is the first day of the week, numeric, four digits; used with %v
%Y : Year, numeric, four digits
%y : Year, numeric (two digits)
%% : A literal % character
%x : x, for any “x” not listed above

%Y-%D-%M로 입력했다가 한참 헤맸다.
항상 생각하고 타이핑 하자.